Please help!!Solve linear-quadratic system algebraically. Show all work.6x + y = –16y + 7 = x^2

Answer:x = - 3 twiceStep-by-step explanation:6x + y = –16 - - - - - - 1y + 7 = x^2 - - - - -2From equation 1, y = - 16 - 6xSubstituting y = - 16 - 6x into equation 2, it becomes- 16 - 6x + 7 = x^2x^2 + 6x + 9 = 0x^2 + 6x + 9 = 0Solving the quadratic equation by factorization method, we will pick two numbers such that their sum is 6x and their product is 9. So we will pick 3x and 3x. It becomesx^2 + 3x + 3x + 9 = 0x(x + 3) + 3(x + 3) = 0(x + 3)(x + 3) = 0x + 3 = 0 or x + 3 =0x = -3 or x =-3Therefore, x = - 3 twiceSubstituting x = - 3 into equation 1, it becomes6 × -3 + y = –16-18 + y = - 16y = - 16 + 18 y = 2