Given the function ƒ(x) = x 2 - 4x - 5Identify the zeros using factorization.Draw a graph of the function. Its vertex is at (2, -9).

Answer:The zeroes of the function f(x) are -1 and 5.Step-by-step explanation:The given function is[tex]f(x)=x^2-4x-5[/tex]The middle term can be written as -5x+x.[tex]f(x)=x^2-5x+x-5[/tex][tex]f(x)=x(x-5)+(x-5)[/tex]Taking out common factors.[tex]f(x)=(x-5)(x+1)[/tex]Equate the given function equal to 0, to get the zeroes.[tex]0=(x-5)(x+1)[/tex]Using zero product property,[tex]x-5=0\Rightarrow x=5[/tex][tex]x+1=0\Rightarrow x=-1[/tex]Therefore the zeroes of the function f(x) are -1 and 5.The vertex of the function is at (2,-9) and the x-intercepts are at (-1,0) and (5,0). So the graph of given function is shown below.