Find the first derivative?

y = 1/(x - 2)   - 3y' = d(x - 2)^-1 / dx   The three is a constant and will disappear.y' = d(x - 2)^-1 -1 d(x - 2)/dxy' = -1*(x - 2)^-2 * 1  The minus comes from bringing down the original power down and reducing the power by one of the question. The 1 at the end comes from differentiating what is inside the brackets. It is called the chain ruled(x - 2) / dx = d(x) / dx which is 1. The two, being a constant, disappears. The final answer isy' = - (x - 2)^-2