A house will be built on a triangular plot of land according to the floor plan. The plot has fronts of 8 meters and 15 meters on two streets that form an angle of 90. How many meters of wall will be needed to surround this plot of land?

Question
Answer:
Since the two streets forming a right angle serve as two sides of the triangle, we need to find the length of the third side, which is the hypotenuse of the right triangle formed by the plot. We can use the Pythagorean theorem to find the length of the hypotenuse (the third side). The theorem states: a² + b² = c² Where: a and b are the lengths of the two shorter sides (in this case, 8 meters and 15 meters). c is the length of the hypotenuse (the third side). Let's calculate it: a = 8 meters b = 15 meters c² = a² + b² c² = 8² + 15² c² = 64 + 225 c² = 289 Now, take the square root of both sides to find c: c = √289 c = 17 meters So, the length of the third side (the hypotenuse) is 17 meters. Now, to find the perimeter of the triangular plot, simply add the lengths of all three sides: Perimeter = 8 meters (one side) + 15 meters (the other side) + 17 meters (the hypotenuse) Perimeter = 8 + 15 + 17 Perimeter = 40 meters Therefore, you will need 40 meters of wall to surround the plot of land.
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general 6 months ago 1354