Consider the two functions given below. f(x) = 3x + 4g(x) = 2^x - 1Which of the following pairs of transformations causes the graphs of the functions to have the same y-intercept?f(x) - 3 and g(x) + 1f(x) + 4 and g(x) - 1f(x) - 2 and g(x) + 1f(x) + 3 and g(x) - 6

This means which transformation makes the same answer at x = 0

f(x) = 3x + 4
[tex] g(x) = {2}^{x} - 1[/tex]

f(0) = 4
g(0) = 1 - 1 = 0

Which transformation makes 4 = 0?

4 + x = 0 + y

4 - 3 =0 + 1

1 = 1

Option 1 is your answer