6(z+2)-2(2z+5)=18 show step by step

[tex]6(z+2)-2(2z+5)=18\\\\6\cdot z+6\cdot2-2\cdot2z-2\cdot5=18\\\\6z+12-4z-10=18\\\\\underbrace{6z-4z}_{2z}+\underbrace{12-10}_{2}=18\\\\2z+2=18\ \ \ |\text{subtract 2 from both sides}\\\\2z=16\ \ \ |\text{divide both sides by 2}\\\\\boxed{z=8}[/tex]