16. A projectile is thrown directly upward at a velocity of 12.0 m/s. How long does it take for theprojectile to reach its maximum height? (g = 9.8 m/s2)A. 0.61 sB. 1.22 sC. 2.45 sD. 2.45 s

It takes 1.22 s for the  projectile to reach its maximum height ⇒ answer BStep-by-step explanation:The given is:A projectile is thrown directly upward at a velocity of 12.0 m/sAcceleration of gravity is g = 9.8 m/s²We need to find how long it takes for the  projectile to reach its maximum heightWhen an object reaches to its maximum height, then its velocity at this maximum height is 0One equation of projectile is v = u + gt, where v is the final velocity, g is the acceleration of gravity, and t is the timeIf the direction of motion is vertically upward, then g = -9.8 m/s²∵ The projectile is thrown directly upward at a velocity of 12 m/s∴ u = 12 m/s and g = -9.8 m/s²∵ It reaches its maximum height∴ v = 0 m/s- Substitute these values in the rule above∴ 0 = 12 - 9.8 t- Add 9.8 t from both sides∴ 9.8 t = 12- Divide both sides by 9.8∴ t = 1.22 secondsIt takes 1.22 s for the  projectile to reach its maximum heightLearn more:You can learn more about equations of free fall in brainly.com/question/4460262#LearnwithBrainly