15 POINTS!!!!!!! What is the equation of the line in slope-intercept form? Line on a coordinate plane. Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.

Answer:[tex]y=\frac{4}{3}x+4[/tex] is the equation of line in slope intercept form.Step-by-step explanation:Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.First ordered pair: (-3,0)Second ordered pair: (0,4)We have two points and need to find equation of line in slope intercept form [tex]\text{Slope (m)}=\dfrac{y_2-y_1}{x_2-x_1}[/tex][tex]\text{Slope (m)}=\dfrac{4-0}{0-(-3)}=\dfrac{4}{3}[/tex]y-intercept, when x=0 , (0,4) Equation of line in slope intercept form:y=mx+bwhere, [tex]m=\frac{4}{3}[/tex] and b=4Required equation:[tex]y=\frac{4}{3}x+4[/tex]Thus, [tex]y=\frac{4}{3}x+4[/tex] is the equation of line in slope intercept form.